every thing is possible with johalputt
Use Lagrange's method to find the maximum value of $<A$*x*, x*$>$ subject to condition $<$*x, x*$> =1$ and $<$*u_1, x**$>=0$ where **u_1 is a non zero vector in $N_{(s_1^2I_n-A^TA)}, s_1$ is the largest singular value of A and $A=A^T \in \mathbb{R}^{n*n})$.
Can anybody please explain me how to proceed with this question?
Use Lagrange's method to find the point on the line of intersection of the two planes $a_1x+a_2y+a_3z+a_0 = 0, b_1x+b_2y+b_3z+b_0 = 0$ which is nearest to the origin. you may also assume that the tow planes really intersect, but you should explain where this enters into the calculation.
I tried to solve this and I reached up to this point:
assuming $g=a_1x+a_2y+a_3z+a_0 = 0, h=b_1x+b_2y+b_3z+b_0 = 0$ and using Lagrange's multiplier method $L(x,y,z,\lambda,\mu) = f -\lambda g -\mu h$ and proceeding by taking the $gradient L =0$; I got the plane $2x^2+2y^2+2z^2 =0$. But the question need a point on the line of intersection of the two planes. How can I find this point?
Vanice is modern magazine blogger template which focuses on lifestyle news, health, and entertainment.
Enter your email address below to subscribe to our newsletter.
Posts
